Comments on: ? jump of chair what earth magnitude of its acceleration and how far does it acutally move up towards you? http://portablefoldinghammock.com/portable-folding-hammocks/jump-of-chair-what-earth-magnitude-of-its-acceleration-and-how-far-does-it-acutally-move-up-towards-you/ The Internet's Most Complete Source Of Portable Folding Hammock Advice, Reviews & Best Prices Sat, 11 Feb 2012 00:00:06 -0600 http://wordpress.org/?v=2.8.2 hourly 1 By: lipglos5ed http://portablefoldinghammock.com/portable-folding-hammocks/jump-of-chair-what-earth-magnitude-of-its-acceleration-and-how-far-does-it-acutally-move-up-towards-you/comment-page-1/#comment-1910 lipglos5ed Thu, 22 Jul 2010 04:49:08 +0000 http://portablefoldinghammock.com/portable-folding-hammocks/jump-of-chair-what-earth-magnitude-of-its-acceleration-and-how-far-does-it-acutally-move-up-towards-you/#comment-1910 I *think* that you must also take into account what is already given to you. Mass of a human = (on average, about) 70kg Mass of Earth = 5.97 x 10^24 Using this, you can first find the force on the person. F = (70kg)(-9.81m/s^2) F = -686.7 N From Newton's third law, we know that the forces are equivalent, meaning F = -F, so we plug it in to find the Earth's acceleration. F = ma 686.7 N = (5.97 x 10^24 kg)(a) a = 1.15 x 10^-22 .....not sure how to work the second part. I hope this helps...Dr. Wiegert's homework problems are really hard (if that's the class you are in). I *think* that you must also take into account what is already given to you.

Mass of a human = (on average, about) 70kg
Mass of Earth = 5.97 x 10^24

Using this, you can first find the force on the person.
F = (70kg)(-9.81m/s^2)
F = -686.7 N

From Newton’s third law, we know that the forces are equivalent, meaning F = -F, so we plug it in to find the Earth’s acceleration.

F = ma
686.7 N = (5.97 x 10^24 kg)(a)
a = 1.15 x 10^-22

…..not sure how to work the second part. I hope this helps…Dr. Wiegert’s homework problems are really hard (if that’s the class you are in).

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