? jump of chair what earth magnitude of its acceleration and how far does it acutally move up towards you?
You stand on the seat of a chair and then hop off.
During the time that you are in the air, the Earth is lurching up toward you. What is the approximate magnitude of the Earth’s acceleration?
No idea where to start other than g=9.81m/s^2
Any clues?
Also have to find : The Earth moves up toward you by approximately what distance?
I *think* that you must also take into account what is already given to you.
Mass of a human = (on average, about) 70kg
Mass of Earth = 5.97 x 10^24
Using this, you can first find the force on the person.
F = (70kg)(-9.81m/s^2)
F = -686.7 N
From Newton’s third law, we know that the forces are equivalent, meaning F = -F, so we plug it in to find the Earth’s acceleration.
F = ma
686.7 N = (5.97 x 10^24 kg)(a)
a = 1.15 x 10^-22
…..not sure how to work the second part. I hope this helps…Dr. Wiegert’s homework problems are really hard (if that’s the class you are in).